The challenge is to find the employees with the second highest salary in each department. However, it is a little more complicated because if two employees have the same salary, you need to list both of them.
Solution to TSQL Beginners Challenge 1
with cte as(
select *, dense_rank() over(partition by department order by salary desc) dr from br_emp )
select EmployeeID,EmployeeName,Department,Salary from cte