Solution to TSQL Beginners Challenge 1

------Solution By Kushal Shah---------
DECLARE @Employees TABLE(
	EmployeeID INT IDENTITY,
	EmployeeName VARCHAR(15),
	Department VARCHAR(15),
	Salary NUMERIC(16,2)
)

INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('T Cook','Finance', 40000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('D Michael','Finance', 25000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('A Smith','Finance', 25000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('D Adams','Finance', 15000)

INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('M Williams','IT', 80000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('D Jones','IT', 40000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('J Miller','IT', 50000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('L Lewis','IT', 50000)

INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('A Anderson','Back-Office', 25000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('S Martin','Back-Office', 15000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('J Garcia','Back-Office', 15000)
INSERT INTO @Employees(EmployeeName, Department, Salary)
VALUES('T Clerk','Back-Office', 10000)


--------------Solution By Kushal Shah---------------
select employeeid,employeename,department,salary 
from(
select employeeid,employeename,department,salary,sortorder=dense_rank() over (partition by department order by salary asc)  
		from (select employeeid,employeename,salary,department from @employees  group by department,employeeid,employeename,salary 
		)as kushal
	)as shah 
where sortorder=2

Tags: